If a #2 kg# object is constantly accelerated from #0m/s# to #16 m/s# over 6 s, how much power musy be applied at #t=1 #?

1 Answer
Feb 14, 2016

#16/3#Newtons

Explanation:

The second Newton's law says

#F=m*a# where #m# is the mass, #F# the power and #a# the acceleration.
As the acceleration is constant #=> a=(v_f -v_0)/t = 16 m/s / 6s = 8/3 m/s^2#
Then, the power applied is #F=2kg*8/3 m/s^2 = 16/3 N#.