How do you solve a/40 = 3/10a40=310?

1 Answer
Feb 15, 2016

a = 12a=12

:)

Explanation:

Since a/b = c/dab=cd,

we can use an algebraic technique, to get the value of aa, by isolation and using the golden rule of algebra, "Balancing the equation"

a/40 = 3/10a40=310

to isolate aa, we must eliminate 4040 in the left side of the equation by multiplying it by 4040, the golden rule of algebra states that whatever you do in a side of an equation is you also must do it in the other side to keep the equation balanced.

(40)a/40 = 3/10(40)(40)a40=310(40)

(cancel40a)/cancel40 = ((40)(3))/10

a = 120/10, we can still simplify the answer giving,

a=12