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What is the sum of a 52–term arithmetic sequence where the first term is 1 and the last term is 154?

1 Answer

Aniket Mahaseth · Veddesh

ϕ

$phi$

Feb 15, 2016

The sum is $4030$ $4030$ .

Explanation:

$S (n) = (\frac{n}{2}) (A 1 + A n)$ $color(blue)(S(n) = (n/2) (A1 + An)$

$\to S (52) = (\frac{52}{2}) (1 + 154)$ $rarrS(52) = (52/2) (1 + 154)$

$\to S (52) = 26 (155)$ $rarrS(52) = 26 (155)$

$\Rightarrow S (52) = 4030$ $rArrS(52) = 4030$

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