The density of platinum is $21.5$ $21.5$ $g$ $g$ $/$ $/$ $c m^{3}$ $cm^3$ at 25°C. What is the volume of 79.5 g of platinum at this temperature?

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The density of platinum is $21.5$ $21.5$ $g$ $g$ $/$ $/$ $c m^{3}$ $cm^3$ at 25°C. What is the volume of 79.5 g of platinum at this temperature?

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Answer 1 · 2016-02-15T08:47:57

The $V o l u m e$ $Volume$ of platninum @ $25^{o} C$ $25^oC$ is $3.70 c m^{3}$ $3.70cm^3$

Explanation:

$G i v e n D a t a :$ $Given Data:$

$D e n s i t y = 21.5 \frac{g}{c m^{3}}$ $Density = 21.5 g/(cm^3)$
$M a s s = 79.5 g$ $Mass= 79.5 g$

$R e q u i r e d :$ $Required:$ $V o l u m e = ?$ $Volume = ?$

$S o l u t i o n :$ $Solution:$

From the formula
$D e n s i t y = \frac{M a s s}{V o l u m e}$ $Density = (Mass)/(Volume)$ ; rearrange to find the volume
$V o l u m e = \frac{M a s s}{D e n s i t y}$ $Volume=(Mass)/(Density)$ ; plug in the given data
$Volume=(79.5cancelg)/(21.5cancelg/(cm^3)$
$Volume=3.70cm^3$

$Answer:$ $3.70cm^3$

Answer 2 · 2016-02-15T08:52:40

Approx. $4$ $cm^3$ .

Explanation:

Density, $rho$ , is simply mass per unit volume, and has units $g*cm^-3$ . So if mass is divided by density, we should get an answer in $1/(cm^-3)$ , i.e. in $cm^3$ .

So, $rho$ $=$ $"Mass"/"Volume"$ ; likewise, $Volume$ $=$ $"Mass"/rho$ :

$"Volume"$ $=$ $(79.5*cancelg)/(21.5*cancelg*cm^-3)$ $=$ $??$ $cm^3$ .

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The density of platinum is $21.5$ $21.5$ $g$ $g$ $/$ $/$ $c m^{3}$ $cm^3$ at 25°C. What is the volume of 79.5 g of platinum at this temperature?

2 Answers

Explanation:

Explanation:

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The density of platinum is 21.521.521.5 ggg///cm^3cm3cm^3 at 25°C. What is the volume of 79.5 g of platinum at this temperature?

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The density of platinum is $21.5$ $21.5$ $g$ $g$ $/$ $/$ $c m^{3}$ $cm^3$ at 25°C. What is the volume of 79.5 g of platinum at this temperature?