If you used 30.6 g of methanol $C H_{3} O H$ $CH_3OH$ to start a fire, how many molecules did you use?

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If you used 30.6 g of methanol $C H_{3} O H$ $CH_3OH$ to start a fire, how many molecules did you use?

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Answer 1 · 2016-02-15T15:30:54

$6.022 \times 10^{23}$ $6.022× 10^23$

Explanation:

this is the Avogadro's number.It is the number of particles found in one mole of a substance. It is the number of atoms in exactly 12 grams of carbon-12.

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If you used 30.6 g of methanol $C H_{3} O H$ $CH_3OH$ to start a fire, how many molecules did you use?

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If you used 30.6 g of methanol $C H_{3} O H$ $CH_3OH$ to start a fire, how many molecules did you use?