How do you solve 3x25x+7=0?

1 Answer
Feb 16, 2016

The roots (answers) are:
x=5+i596
and,
x=5i596

Hence there are no real roots to this quadratic, which means it does not cross the x-axis.

Explanation:

3x25x+7=0 is a quadratic equation. This can be solved in 3 ways: factorising, using the quadratic formula or by completing the square. It's not obvious how to factorise 3x25x+7=0 so we'll use the quadratic formula:

x=b±b24ac2a

a is the coefficient of x2, in this case 3.
b is the coefficient of x, in this case -5.
c is the constant, in this case 7.

Putting these values into the quadratic equation:
x=(5)±(5)24(3)(7)2(3)
x=5±25846
x=5±596
x=5±i596

So the roots are:
x=5+i596
and,
x=5i596

59 is an imaginary number, equal to 159, which equals i59. The symbol for the square root of -1 is i. Thus the roots of this equation have a real part (the 5/6) and an imaginary part (the ±i596). A number made up of a real and imaginary part is called a complex number. Hence there are no real roots to this quadratic, which means it does not cross the x-axis.