How do you solve #2x^2+5x= - 4# using the quadratic formula?

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Answer 1 · 2016-02-19T20:39:48

(#-b + or -# #sqrt(#b^2 -4(a)(C)))÷(#2a) quadratic formula must equal zero

x

− #b^2# ±√b−4ac

2a

move 4 to the other side so

#2x^2 + 5x + 4=0#

#2x^2=a#
#5x=b#
#4=c#