How do you find the domain & range for $y = arccos x$ $y=Arccos x$ ?

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How do you find the domain & range for $y = arccos x$ $y=Arccos x$ ?

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Answer 1 · 2016-02-20T12:07:50

[0, $π$ $pi$ ]

Explanation:

When cos x varies in [ $-$ $-$ 1, 1 ].
If cos x is positive, the angle y is in the first quadrant, [ 0, $π$ $pi$ /2 ]. Otherwise, it is in the second, [ $π$ $pi$ /2, $π$ $pi$ ].

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How do you find the domain & range for $y = arccos x$ $y=Arccos x$ ?

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How do you find the domain & range for $y = arccos x$ $y=Arccos x$ ?