Question

If a projectile is shot at a velocity of `7 m/s` and an angle of `pi/4`, how far will the projectile travel before landing?

Answer 1

1.25m

Explanation:

The range of a projectile is calculated as

`x=(v^2.sin^2 alpha)/(2.g)`

`here, V=7,alpha=45` `g=9.8m/s^2`

= `(7^2.(1//sqrt2)^2)/(2. 9.8)`

= `((49/2))/19.6`

=1.25m