What is the implicit derivative of #25=yx^2-xy+y^2x#?

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Answer 1 · 2016-02-22T00:13:13

Using the chain and product rules ...

#25=yx^2-xy+y^2x#

#0=y'(x^2)+y(2x)-y-xy'+2yy'x+y^2#

Next, solve for #y'#

#y'(x^2-x+2xy)=-(2xy-y+y^2)#

#y'=-(2xy-y+y^2)/(x^2-x+2xy)#

hope that helped