What is the implicit derivative of $25=yx^2-xy+y^2x$ ?

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Answer 1 · 2016-02-22T00:13:13

Using the chain and product rules ...

$25=yx^2-xy+y^2x$

$0=y'(x^2)+y(2x)-y-xy'+2yy'x+y^2$

Next, solve for $y'$

$y'(x^2-x+2xy)=-(2xy-y+y^2)$

$y'=-(2xy-y+y^2)/(x^2-x+2xy)$

hope that helped

What is the implicit derivative of 25=yx^2-xy+y^2x25=yx^2-xy+y^2x?