What is the standard form of $y = (x - 8) {(x - 1)}^{2}$ $y= (x - 8) (x -1)^2$ ?

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What is the standard form of $y = (x - 8) {(x - 1)}^{2}$ $y= (x - 8) (x -1)^2$ ?

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Answer 1 · 2016-02-24T01:12:12

$y = x^{3} - 10 x^{2} + 17 x - 8$ $y = x^3 -10x^2 +17x-8$

Explanation:

Step 1: Multiply and expand the function and combine like terms

$y = (x - 8) {(x - 1)}^{2}$ $y= (x-8)(x-1)^2$

$y = (x - 8) (x - 1) (x - 1)$ $y = (x-8)(x-1)(x-1)$
$y = (x^{2} - 8 x - x + 8) (x - 1)$ $y= (x^2-8x-x+8)(x-1)$
$y = (x^{2} - 9 x + 8) (x - 1)$ $y= (x^2 -9x +8)(x-1)$

*Step 28: Multiply and expand and combine like terms like this

$y = (x^{2} - 9 x + 8) (x - 1)$ $y= (x^2 -9x +8)(x-1)$

$y = (x^{3} - x^{2} - 9 x^{2} + 9 x + 8 x - 8)$ $y = (x^3 -x^2 -9x^2 +9x +8x-8)$
$y = x^{3} - 10 x^{2} + 17 x - 8$ $y = x^3 -10x^2 +17x-8$

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What is the standard form of $y = (x - 8) {(x - 1)}^{2}$ $y= (x - 8) (x -1)^2$ ?

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Explanation:

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What is the standard form of y=(x−8)(x−1)2 y= (x - 8) (x -1)^2 ?

1 Answer

Explanation:

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What is the standard form of $y = (x - 8) {(x - 1)}^{2}$ $y= (x - 8) (x -1)^2$ ?