How do you factor the trinomial $12 x^{2} - 6 x - 18$ $12x^2-6x-18$ ?

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Answer 1 · 2016-02-24T13:33:57

$6 (2 x - 3) (x + 1)$ $6(2x-3)(x+1)$

Frist take out any common factors.

$12 x^{2} - 6 x - 18 = 6 (2 x^{2} - x - 3)$ $12x^2 - 6x -18 = 6(2x^2 - x - 3)$

The factors of $2$ $2$ are $2$ $2$ and $1$ $1$ , and the factors of $3$ $3$ are $3$ $3$ and $1$ $1$ .

The expression is therefore $6 (2 x - 3) (x + 1)$ $6(2x-3)(x+1)$

How do you factor the trinomial 12x2−6x−1812x^2-6x-18?