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How do you differentiate $ln (x + y)$ $ln(x+y)$ ?

1 Answer

Feb 25, 2016

Use implicit differentiation ...

Explanation:

$f (x) = ln (x + y)$ $f(x)=ln(x+y)$

$f'(x)=1/(x+y)xx(1+y')$

hope that helped

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