A box contains 3 red balls and 4 green balls. If two balls are randomly selected in sequence, what is the possibility that a red ball and a green ball are picked out of the box?

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A box contains 3 red balls and 4 green balls. If two balls are randomly selected in sequence, what is the possibility that a red ball and a green ball are picked out of the box?

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Answer 1 · 2016-02-26T00:18:15

There are 3 ways to pick the red ball and 4 ways to pick the green ball for a total number of events of $3 \times 4 = 12$ $3xx4=12$ ways to pick a red and green ball out of the box.

Explanation:

There is a total of 7 balls. The sample space for the number of ways of choosing two balls is $\frac{7!}{2! 5!} = 21$ $(7!)/(2!5!)=21$ ways

P(red ball and a green ball) $= \frac{12}{21} = \frac{4}{7} \approx 0.57$ $=12/21=4/7~~0.57$

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A box contains 3 red balls and 4 green balls. If two balls are randomly selected in sequence, what is the possibility that a red ball and a green ball are picked out of the box?

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