A 4.0 kilogram object moving west at 8.0 meters per second is subjected to a force to the east for 1.5 seconds, slowing it down to a speed of 2.0 meters per second. What was the net force that was applied?
1 Answer
Feb 28, 2016
This question relates to Newton's 2nd law.
Explanation:
Newton's 2nd law may be defined as
In the above, v= final velocity, u = initial velocity.
Applying to the above scenario:
F = [(3x2) -(3x8)]/1.5 = [6-24]1.5 =12N acting in the East direction