How many atoms are present in 4.00 mol of aluminum?

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How many atoms are present in 4.00 mol of aluminum?

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Answer 1 · 2016-02-29T12:53:06

To determine the amount of atoms (or molecules) present given the moles of an element, you multiply the amount of moles by Avogadro's number, $6.022 \cdot 10^{23}$ $6.022*10^23$

4 mol $A l$ $Al$ $\frac{6.022 \cdot 10^{23}}{1 m o l}$ $(6.022*10^23)/(1 mol)$ = $2.41 \cdot 10^{24}$ $2.41*10^24$ atoms/molecules of $A l$ $Al$

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How many atoms are present in 4.00 mol of aluminum?

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