What is the molarity of a solution prepared by dissolving 141.6 g of citric acid, C3H5O(COOH)3, in water and then diluting the resulting solution to 3500.0 mL?

1 Answer
Feb 29, 2016

.2106M C3H5O(COOH)3

Explanation:

Molarity is defined as the mols of a compound/element over 1 liter of solution

M(Molarity)= Mols1Lsolution

you first need to convert 141.6g of citric acid into mols

C = 12.01g * 6 = 72.06g
H = 1.0079g * 8 = 8.0632g
O = 16.00g * 7 = 112.0g
C3H5O(COOH)3= 192.12g

141.6g C3H5O(COOH)3 1molC3H5O(COOH)3192.12g=.7370 mol C3H5O(COOH)3

We not have the mols of C3H5O(COOH)3, and we are given it is diluted to 3500.0 mL

3500.0 mL 1Liter1000mL=3.5000L

plug both the mols of C3H5O(COOH)3 and L of C3H5O(COOH)3 into

M(Molarity)= Mols1Lsolution

M(Molarity)= .7370mol3.5000Lsolution

M= .2106

.2106M C3H5O(COOH)3