What is the slope intercept form of the line passing through #(24,6) # with a slope of #3/2 #?

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Answer 1 · 2016-02-29T13:06:54

#3x-2y-60=0#

Equation of line passing through a point #(x_1,y_1)# and having a slope of #m# in point-slope form is given by #(y-y_1)=m)x-x_1)#

Hence equation of line passing through #(24,6)# and having slope #3/2# will be

#(y-6)=(3/2)xx(x-24)# or #2(y-6)=3x-72# or

#3x-2y-60=0#

Answer 2 · 2016-02-29T13:10:28

The equation is #y = (3/2)x -30#

The equation is of the form

#y = mx + c#
Where
#m# is the slope of the line (given as #3/2#)
and #c# is the slope intercept

Substituting in the values from the question
#6=(3/2).24 + c#

simplifying
6=36 +c

c = -30

The equation is #y = (3/2)x -30#