A gas occupies a volume of 0.6 L at 10.1 kPa. What volume will the gas occupy at 101 kPa?

1 Answer
Stefan V. · Wil052
Feb 29, 2016

".06 L".06 L

Explanation:

Use the equation for Boyle's Law

P_1V_1 = P_2V_2P1V1=P2V2

Plug in your values to get

("10.1 kPa") xx (".6 L") = ("101 kPa") xx V_2(10.1 kPa)×(.6 L)=(101 kPa)×V2

[(10.1cancel("kPa"))(".6 L")]/(101cancel("kPa"))= V_2

V_2 = ".06 L"

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