An astronaut with a mass of 85 kg is floating in space. If the astronaut throws an object with a mass of 20 kg at a speed of 5/8 m/s, how much will his speed change by?

1 Answer
Mar 1, 2016

0.15m/s backward

Explanation:

This can be solved using the law of conservation of momentum. The formula is:

M_1V_1 + M_2V_2=M_1V_1' + M_2V_2')

Given:

M_1=85kg
V_1=0 m/s (at rest)
M_2=20kg
V_2=0 m/s(at rest)
V_2'=5/8 m/s

Required: V_1'= ?

Solution:

  1. Use the formula reflected above and plug in data provided in the problem.

2.Initial speeds of the astronaut and the object are zeros since both are at rest.

3.Just remember that momentum is being conserved after throwing the object 5/8 m/s to the space.

Answer:

-0.15 m/s or 0.15 m/s backward