How do you find the slope perpendicular to $x - y = 16$ $x - y = 16$ ?

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How do you find the slope perpendicular to $x - y = 16$ $x - y = 16$ ?

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Answer 1 · 2016-03-01T04:52:25

Slope(m)= $- 1$ $-1$

Explanation:

We know that,The equation of a straight line is given by,
$y = m x + c$ $y=mx + c$
where, m represents the gradient or slope and c represents y - intercept.

Comparing the given equation with $y = m x + c$ $y = mx + c$ we get,

$y = x - 16$ $y = x - 16$
$y = (- 1) x + 16$ $y = (-1) x + 16$
i.e ( $= y = m x + c)$ $=y=mx+c)$

So slope(m)= $- 1$ $-1$

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How do you find the slope perpendicular to $x - y = 16$ $x - y = 16$ ?

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Explanation:

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How do you find the slope perpendicular to x−y=16x - y = 16?

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Explanation:

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How do you find the slope perpendicular to $x - y = 16$ $x - y = 16$ ?