How do you calculate the percentage composition of Oxygen in $N_{2} O_{5}$ $N_2O_5$ ?

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Answer 1 · 2016-03-01T14:29:48

$25.93 %$ $25.93%$ $N$ $N$ , $74.07 %$ $74.07%$ $O$ $O$

You first need refrence a periodic table to find the weight of $N$ $N$ and $O$ $O$

$N$ $N$ = $14.0 g$ $14.0g$
$O$ $O$ = $16.0 g$ $16.0g$

Multiply each element based on how many of each element are in the compound. for $N$ $N$ , it is 2. For $O$ $O$ , it is 5.

$14.0 g$ $14.0g$ $O$ $O$ * 2 = $28.0 g$ $28.0g$ $N$ $N$

$16.0 g$ $16.0g$ $O$ $O$ * 5 = $80.0 g$ $80.0g$ $O$ $O$

add the two weights together to get the total weight of $N_{2} O_{5}$ $N_2O_5$

$28.0 g$ $28.0g$ + $80.0 g$ $80.0g$ = $108 g$ $108g$ $N_{2} O_{5}$ $N_2O_5$

Divide each elements weight by the total weight of the compound and multiply by 100 and you will have the percentage composition

$\frac{28.0 g N}{108 g}$ $(28.0gN)/(108g)$ * 100 = $25.93 %$ $25.93%$ $N$ $N$

$\frac{80.0 g O}{108 g}$ $(80.0gO)/(108g)$ * 100 = $74.07 %$ $74.07%$ $O$ $O$

How do you calculate the percentage composition of Oxygen in N2O5N_2O_5?