If sin(t)=0.8 and cos(t)=0.6. what is sin(t)+cos(-t)+sin(-t+2pi)?

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Answer 1 · 2016-03-02T05:57:50

0.6

From given data,

#sint=0.8# & #cos t=0.6#

Let #x=sint+cos(-t)+sin(2pi-t)#

[#cos(-t)=cost & sin(2pi-t)=-sint#]

#:.x=sint+cost-sint#

#=>x=cancelsint+cost-cancelsint#

#=>x=cost#

#:.x=0.6#