A rectangular floor measuring 8 feet by 6 feet is to be completely covered with square tiles measuring 8 inches on side. How many tiles are needed to completely cover the floor?

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A rectangular floor measuring 8 feet by 6 feet is to be completely covered with square tiles measuring 8 inches on side. How many tiles are needed to completely cover the floor?

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Answer 1 · 2016-03-02T12:00:48

$108$ $108$

Explanation:

First we need to get everything into the same units, whether feet or inches. If we choose inches, then we can say that the floor is $96$ $96$ inches by $72$ $72$ inches.
To find how many tiles are need, we need to find out how many time $8$ $8$ fits into each of the floor's dimensions.
$\frac{96}{8} = 12$ $96/8 = 12$
$\frac{72}{8} = 9$ $72/8 = 9$

We can therefore fit $12$ $12$ rows of tiles with $9$ $9$ tiles in each row. This means there are $12 \cdot 9 = 108$ $12 * 9 = 108$ tiles.

Answer 2 · 2016-03-02T13:09:57

$108$ $108$

Explanation:

First we need to convert the units to the same extent.

$1 f e e t = 12 i$ $1feet=12 i$ $n c h e s$ $nches$

$:.8 feet=8*12=96$

$6 feet=6*12=72 i$ $nches$

If we think,We could find that

No.of tiles=Area of rectangle / Area of each square

$Area$ $of$ $recta$ $ngl$ $e$ $=lb=96*72$

$Area$ $of$ $each$ $squ$ $are$ $=s^2=8^2=64$

$:.rarr=(cancel96*72)/cancel64$

$rarr=(cancel24*72)/cancel16$

$rarr=(6*cancel72)/cancel4$

$rarr=6*18=108$

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A rectangular floor measuring 8 feet by 6 feet is to be completely covered with square tiles measuring 8 inches on side. How many tiles are needed to completely cover the floor?

2 Answers

Explanation:

Explanation:

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