How do you evaluate #Sin((5pi)/12) cos(pi/4) - cos((5pi)/12) sin(pi/4)#?
2 Answers
Mar 3, 2016
Explanation:
To evaluate
Hence
=
=
Mar 3, 2016
Explanation:
Trig identity: sin (a - b) = sin a.cos b - sin b.cos a.
Therefor, the expression is reduced to: