A spring with a constant of 9 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 2 kg and speed of 7 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer
Mar 4, 2016

Delta x=7/3sqrt2" " m

Explanation:

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E_k=1/2*m*v^2" The Kinetic Energy of Object"
E_p=1/2*k*Delta x^2
"The Potential Energy of Spring Compressed"
E_k=E_p" Conservation of Energy"
cancel(1/2)*m*v^2=cancel(1/2)*k*Delta x^2
m*v^2=k*Delta x^2
2*7^2=9*Delta x^2
Delta x=sqrt(2*7^2/9)
Delta x=7/3sqrt2" " m