How do you factor the expression $2 x^{2} + 9 x - 5 = 0$ $2x^2 + 9x - 5 = 0$ ?

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How do you factor the expression $2 x^{2} + 9 x - 5 = 0$ $2x^2 + 9x - 5 = 0$ ?

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Answer 1 · 2016-03-05T21:38:16

$(2 x - 1) (x + 5)$ $(2x-1)(x+5)$

Explanation:

Open two sets of brackets.

The first expression, $2 x^{2}$ $2x^2$ only has two possible factors, $2 x$ $2x$ and $x$ $x$ . Put them into the brackets. $(2 x) (x)$ $(2x )(x )$

Multiply the first and last coefficients; -5 x 2 = -10. The factors of -10 are: -1, 10; -2, 5; 2, -5; and 1, -10. Add each. The first result is +9, which is the middle expression in the original question.

But one of your factors is $2 x$ $2x$ , so divide by 2. --> $\frac{10}{2} = 5$ $10/2=5$

Put into the brackets. $(2 x - 1) (x + 5)$ $(2x - 1)(x+5)$

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How do you factor the expression $2 x^{2} + 9 x - 5 = 0$ $2x^2 + 9x - 5 = 0$ ?

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