Question #c5b12

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Question #c5b12

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Answer 1 · 2016-03-09T15:06:25

$\frac{2}{7}$ $2/7$

Explanation:

the first friend has $7$ $7$ books to choose from, $3$ $3$ of which are mystery books. Therefore there are $3$ $3$ out of $7$ $7$ chances that the first friend will choose a mystery book. Probability of $\frac{3}{7}$ $3/7$

Once this happens, the second friend is choosing from $6$ $6$ books, $2$ $2$ of which are mystery books and $4$ $4$ of which are romance books. The second friend therefore has $4$ $4$ out of $6$ $6$ chances of picking a romance book - probability of $\frac{4}{6} = \frac{2}{3}$ $4/6 = 2/3$ .

The probability of both these events happening is the product of the two probabilities, so $\frac{3}{7} \cdot \frac{2}{3} = \frac{2}{7}$ $3/7*2/3 = 2/7$

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