What is the value of 6x^2+4x+8 when x=7?

1 Answer
Wayne
Mar 9, 2016

The value of the trinomial 6x^2+ 4x + 8 when x=7 is 330

Explanation:

The variable in this question is x, which in this case we are told has a value of 7 because we are given x=7. By substituting this value for x into the trinomial in place of x we get:
6(7)^2+4(7)+8
6(49)+28+8
294+28+8 = 330

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