Deers and roes live in the forest. Deers make up 30% of the forest life. There are 144 deers less than roes. How many roes live in the forest? Answer: 252 roes. How do I solve this problem?

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Deers and roes live in the forest. Deers make up 30% of the forest life. There are 144 deers less than roes. How many roes live in the forest? Answer: 252 roes. How do I solve this problem?

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Answer 1 · 2016-03-10T09:00:49

Convert the problem into equations that can be solved for the number of roe.

Explanation:

If $x$ $x$ is the number of roes, then the number of deer is $x - 144$ $x-144$

If $T$ $T$ is the total, then deer are $0.3 \cdot T$ $0.3*T$

$x + (x - 144) = T$ $x+(x-144)=T$
$2 x = T + 144$ $2x = T +144$

$x - 144 = 0.3 \cdot T$ $x-144 = 0.3*T$
$x = \frac{3 T}{10} + 144$ $x= (3T)/10 +144$

Substituting, $2 (\frac{3 T}{10} + 144) = T + 144$ $2((3T)/10 +144) = T+144$
$\frac{3 T}{5} - T = 144 - 288$ $(3T)/5 -T = 144 - 288$
$2 T = 144 \cdot 5 = 720$ $2T = 144*5 = 720$

$T = 360$ $T = 360$

$x = 108 + 144 = 252$ $x=108 + 144 = 252$

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Deers and roes live in the forest. Deers make up 30% of the forest life. There are 144 deers less than roes. How many roes live in the forest? Answer: 252 roes. How do I solve this problem?

1 Answer

Explanation:

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