How do you solve #y+2x=5# and #2x^2 - 3x - y =16#?
2 Answers
Explanation:
In this way:
so:
So:
Explanation:
Given:
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Write equation (1) as:
Write equation (2) as:
Equate equation
Collecting like terms and equation to 0
Solving by quadratic formula method
Standard form
Where:
Thus we have: