How do you find the definite integral of $\int (1 - 2 x - 3 x^{2}) d x$ $int (1-2x-3x^2)dx$ from $[0, 2]$ $[0,2]$ ?

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How do you find the definite integral of $\int (1 - 2 x - 3 x^{2}) d x$ $int (1-2x-3x^2)dx$ from $[0, 2]$ $[0,2]$ ?

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Answer 1 · 2016-03-11T22:26:25

$\int_{0}^{2} (1 - 2 x - 3 x^{2}) d x = - 10$ $int_0^2(1-2x-3x^2)d x=-10$

Explanation:

$\int_{0}^{2} (1 - 2 x - 3 x^{2}) d x = {∣ ∣ ∣ x - 2 \cdot \frac{1}{2} \cdot x^{2} - 3 \cdot \frac{1}{3} \cdot x^{3} ∣ ∣ ∣}_{0}^{2}$ $int_0^2(1-2x-3x^2)d x=|x-2*1/2*x^2-3*1/3*x^3|_0^2$
$\int_{0}^{2} (1 - 2 x - 3 x^{2}) d x = {∣ ∣ x - x^{2} - x^{3} ∣ ∣}_{0}^{2}$ $int_0^2(1-2x-3x^2)d x=|x-x^2-x^3|_0^2$
$\int_{0}^{2} (1 - 2 x - 3 x^{2}) d x = 2 - 2^{2} - 2^{3}$ $int_0^2(1-2x-3x^2)d x=2-2^2-2^3$
$\int_{0}^{2} (1 - 2 x - 3 x^{2}) d x = 2 - 4 - 8$ $int_0^2(1-2x-3x^2)d x=2-4-8$
$\int_{0}^{2} (1 - 2 x - 3 x^{2}) d x$ $int_0^2(1-2x-3x^2)d x$
$\int_{0}^{2} (1 - 2 x - 3 x^{2}) d x = - 10$ $int_0^2(1-2x-3x^2)d x=-10$

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How do you find the definite integral of $\int (1 - 2 x - 3 x^{2}) d x$ $int (1-2x-3x^2)dx$ from $[0, 2]$ $[0,2]$ ?

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Explanation:

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How do you find the definite integral of ∫(1−2x−3x2)dxint (1-2x-3x^2)dx from [0,2][0,2]?

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Explanation:

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How do you find the definite integral of $\int (1 - 2 x - 3 x^{2}) d x$ $int (1-2x-3x^2)dx$ from $[0, 2]$ $[0,2]$ ?