Question

Two charges of `9 C` and `2 C` are positioned on a line at points `6` and `-4`, respectively. What is the net force on a charge of `3 C` at `2`?

Answer 1

`F_"net"=13,69*10^9" "N`

Explanation:

`"The force between two charges is given as : "F=k(q_1 q_2)/d^2`
`F_"B C"=k(9*3)/4^2=(27k)/16`
`F_"A C"=k(2*3)/6^2=(6k)/36`
`F_"net"=F_"B C"-F_"A C"`
`F_"net"=(27k)/16-(6k)/36`
`F_"net"=k(27/16-1/6)`
`F_"net"=146/96*k`
`k=9*10^9 N*m^2*C-^2`
`F_"net"=146/96*9.10^9`
`F_"net"=13,69*10^9" "N`