An object, previously at rest, slides 15 m down a ramp, with an incline of pi/3 , and then slides horizontally on the floor for another 12 m. If the ramp and floor are made of the same material, what is the material's kinetic friction coefficient?

1 Answer
Mar 13, 2016

mu=(5sqrt3)/13

Explanation:

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"Total Energy at The Point of A:"
E_A=m*g*h
"Work Doing by The Friction Force Along AB:"
W_"AB"=mu*m*g*cos (pi/3)*15
"Work Doing by The Friction Force Along BD:"
W_"BD" =mu*m*g*12
E_A=W_"AB" +W_"BD"
cancel(m*g)*h=mu*cancel(m*g)*cos(pi/3)*15+mu*cancel(m*g)*12
h=mu*15*cos(pi/3)+mu*12*
alpha=pi/3
h=15*sin(pi/3)
15*sin(pi/3)=mu(15*cos(pi/3)+12)
15*sqrt3/2=mu(15*1/2+12)
7,5sqrt3=mu(39/2)
15sqrt3=mu*39
mu=(15sqrt3)/39
mu=(5sqrt3)/13