Question

Question #3069c

Answer 1

`{(x=1),(y=0):}`

Explanation:

If you meaning:

`{(x=1-y, "S1"),(y=2x-2,"S2"):}`

Using the Systems solving method Using Substitution you have already explicitated `x` in `S1`, then you have to substitute it in `S2` as you said:

`{(x=1-y, "S1"),(y=2(1-y)-2,"S2"):}`

Then you solve `S2` in `y`

`{(x=1-y, "S1"),(y=cancel(2)-2ycancel(-2),"S2"):}`

`{(x=1-y),(y+2y=0):}<=>{(x=1-y),(3y=0):}<=>{(x=1-y),(y=0):}`

Now you substitute `y=0` in the equation `S1`

`{(x=1-0, "S1"),(y=0,"S2"):}`

`:.{(x=1),(y=0):}`

In a `XY` plot, the system solution is the point where `S1` intercept `S2`:

graph{(y+x-1)(y-2x+2)=0 [-10, 10, -5, 5]}