Question #3069c

Question

886 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-14T12:57:51

${(x=1),(y=0):}$

If you meaning:

${(x=1-y, "S1"),(y=2x-2,"S2"):}$

Using the Systems solving method Using Substitution you have already explicitated $x$ in $S1$ , then you have to substitute it in $S2$ as you said:

${(x=1-y, "S1"),(y=2(1-y)-2,"S2"):}$

Then you solve $S2$ in $y$

${(x=1-y, "S1"),(y=cancel(2)-2ycancel(-2),"S2"):}$

${(x=1-y),(y+2y=0):}<=>{(x=1-y),(3y=0):}<=>{(x=1-y),(y=0):}$

Now you substitute $y=0$ in the equation $S1$

${(x=1-0, "S1"),(y=0,"S2"):}$

$:.{(x=1),(y=0):}$

In a $XY$ plot, the system solution is the point where $S1$ intercept $S2$ :

graph{(y+x-1)(y-2x+2)=0 [-10, 10, -5, 5]}