Question #b5376

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Answer 1 · 2016-03-15T04:41:01

$8.3997$ $8.3997$ x $10^{25}$ $10^25$ atoms of $C u$ $Cu$

We need to balance the equation to determine the mole ratio of $C u$ $Cu$ against the $C u_{3} F e S_{3}$ $Cu_3FeS_3$ ;
The balanced equation is:
$2 C u_{3} F e S_{3} + 7 O_{2} \to 6 C u = 2 F e O + 6 S O_{2}$ $2Cu_3FeS_3 + 7O_2 -> 6Cu = 2FeO + 6SO_2$
Find the formula mass of bornite, by locating the atomic masses of the elements composing the copper ore, which is equal to 344 grams per mole;
To start the calculation, you are provided with the mass of the raw material of $20 k g$ $20 kg$ which has 80% purity. Meaning $80 %$ $80%$ of the raw material is bornite (copper ore). To find the mass of copper ore, multiply the mass by its purity; so that
$20 k g$ $20 kg$ x $0.80 = 16 k g$ $0.80=16 kg$ of pure bornite
Convert the mass (kg) of pure bornite to grams to be consistent with the units being used in the formula mass; ( $16, 000$ $16,000$ grams)
Again, $16, 000$ $16,000$ grams bornite will be converted to mole bornite by multiplying with the mole ratio reflected on the balanced equation above to arrive $139.53$ $139.53$ mole $C u$ $Cu$ ;
Since $1 m o l C u = 6.02$ $1 mol Cu=6.02$ x $10^{23}$ $10^23$ atoms $C u$ $Cu$ , multiply the answer in step 6 by the conversion factor taken from this equaivalent statement, which is $\frac{6.02 x 10^{23} a t m s C u}{1 m o l C u}$ $(6.02 x 10^23 atms Cu)/(1 mol Cu)$ ;
The answer is computed as 8.3997 x $10^{25}$ $10^25$ atoms $C u$ $Cu$