How do you write the equation in point slope form given (-3,1); (0,2)?

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How do you write the equation in point slope form given (-3,1); (0,2)?

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Answer 1 · 2016-03-15T14:58:16

y= $\frac{1}{3} x + 2$ $1/3x + 2$

Explanation:

The general form of a linear equation is $y = m x + b$ $y=mx+b$ where $m$ $m$ is the slope and $b$ $b$ is the y-intercept. In this case the point $(0, 2)$ $(0,2)$ is located on the y axis and is infact the y-intercept. So, in our general formula, $b = 2$ $b=2$ . To find the slope we use the formula:
$m$ $m$ = $(\frac{y_{2} - y_{1}}{x_{2} - x_{1}})$ $(( y_2 - y_1)/(x_2 - x_1))$

$m$ $m$ = $(\frac{2 - 1}{0 - - 3})$ $((2 - 1)/(0 - -3))$ = $\frac{1}{3}$ $1/3$
Using these two bits of information I can write the equation as:
$y = \frac{1}{3} x + 2$ $y=1/3x +2$

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How do you write the equation in point slope form given (-3,1); (0,2)?

1 Answer

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