Question

How do you find the intercepts of `4x-3y=12`?

Answer 1

`x` intercept: `(3,0)`
`y` intercept `(0;-4)`

Explanation:

You have to evaluate the equation for `x=0` and `y=0`

1. `x_nn = x` intercept:
   `{(4x-3y=12),(y=0):}=>4x=12=>x=12/4=3=>P_(x_nn)(3;0)`

2. `y_nn=y` intercept
   `{(4x-3y=12),(x=0):}=>-3y=12=>y=-12/3=-4=>P_(y_nn)(0;-4)`

graph{4x-3y-12=0 [-10, 10, -5, 5]}