How do you find the derivative of #-2x(x^2+3)^-2#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Bdub · Shwetank Mauria Mar 17, 2016 #d/dx=(6x^2-6)/((x^2+3)^3# Explanation: #f=-2x,g=(x^2+3)^-2# #f'=-2,g'=-2(x^2+3)^-3 *2x# #(df)/(dx)=(8x^2)/(x^2+3)^3 -2/((x^2+3)^2# #(df)/(dx)=(8x^2-2(x^2+3))/((x^2+3)^3# #(df)/(dx) = (8x^2-2x^2-6)/((x^2+3)^3# #(df)/(dx)=(6x^2-6)/((x^2+3)^3# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1547 views around the world You can reuse this answer Creative Commons License