What is the vertex of y= x^2 - 4xy=x2−4x?

1 Answer
Vikki
Mar 18, 2016

Vertex is at (2, -4)(2,−4)

Explanation:

color(red)(x_(vertex) = -b/(2a)) ;color(blue)( y_(vertex) = f(-b/(2a))xvertex=−b2a;yvertex=f(−b2a) given the equation in the standard form of ax^2 + bx+cax2+bx+c

Given :y = x^2 - 4x + 0y=x2−4x+0

a= 1, b = -4 , c= 0a=1,b=−4,c=0

color(red)(x_(vertex)) = (-(-4))/(2*1) = 4/2 = color(red)(2)xvertex=−(−4)2⋅1=42=2

color(blue)(y_(vertex))= f(2) = (2)^2-4(2) = 4-8 =color(blue)(-4)yvertex=f(2)=(2)2−4(2)=4−8=−4

Vertex : (x, y) = (2, -4)(x,y)=(2,−4)

graph{x^2-4x [-6.43, 7.62, -5.635, 1.39]}

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