How do you differentiate f(x)=√sin(2−x3) using the chain rule?

1 Answer
Azhar A.
Mar 19, 2016

dydx=−12[√sin(2−x3)]cos(2−x3)⋅3x2

Explanation:

Let y=√sin(2−x3)

Differentiating w.r.t. x

dydx=ddx√sin(2−x3)

dydx=12[√sin(2−x3)]⋅ddxsin(2−x3)

dydx=12[√sin(2−x3)]cos(2−x3)⋅ddx2−x3

dydx=12[√sin(2−x3)]cos(2−x3)⋅(−3x2)

dydx=−12[√sin(2−x3)]cos(2−x3)⋅3x2

This will be the differentiated function.

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