Question

How do you solve `(9y)/14 + 3/7- =9/14`?

Answer 1

`y=0,bar(3)`

Explanation:

`(9y)/14=9/14-3/7`

`(9y)/cancel(14)=((7*9)-(3*14))/(cancel(14)*7)`

`y=((7*9)-(3*14))/(9*7)`
`y=(63-42)/63`
`y=0,bar(3)`

Answer 2

y = `1/3`

Explanation:

`(9y)/14 + 3/7 = 9/14`

Firstly change all denominators to 14 g
giving
`(9y)/14 +6/14 = 9/14`
Now you can ignore the denominators to get
9y + 6 = 9
Subtract 6 from both sides
9y = 3
Divide both sides by 9
y = `3/9`
which simplifies to
y = `1/3`