How do you determine if #f(x)=8x^6 + 12x^2# is an even or odd function?

2 Answers
Mar 20, 2016

It's an even function.

Explanation:

One of the easy ways to determine weather a function is even or odd is to look at the powers of #x#. If all the powers of #x# are even, such as #8x^6+12x^2# (powers are #6# and #2#), then it's an even function. If all the powers of #x# are odd, such as #5x^3+##x# (powers of #x# are #3# and #1#) , then it's an odd function.

Also remember that a function can be neither odd or even function, such as;
#f(x)=5x^3+x^4#

Mar 20, 2016

Verify #f(-x) = f(x)# for all #x in RR#, so #f(x)# is even.

Explanation:

#f(-x) = 8(-x)^6+12(-x)^2 = 8x^6+12x^2 = f(x)# for all #x in RR#

So #f(x)# is even.

For polynomial functions, there is a quick shortcut:

If all of the terms have even degree then the function is even. Remember that a constant term is of degree #0# which is even.

If all of the terms have odd degree, then the function is odd.

If the terms are a mixture of odd and even degrees then the function is neither even nor odd.