How do you find the slope given y+3=-1/3x?

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How do you find the slope given y+3=-1/3x?

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Answer 1 · 2016-03-22T00:03:47

The slope is $- \frac{1}{3}$ $-1/3$

Explanation:

Your equation may be rewritten into what we call the slope/intercept form: $y = m x + b$ $y = mx+b$ where $m$ $m$ represents the slope of the equation.

$y + 3 = - \frac{1}{3} x$ $y+3=-1/3x$ Subtract 33# from both sides of the equation

$y + 3 - 3 = - \frac{1}{3} x - 3$ $y+3-3=-1/3x-3$

$y = - \frac{1}{3} x - 3$ $y = -1/3x -3$ Now compare this equation to the slope/intercept form $y = m x + b$ $y =mx+b$ , and we easily see that the slope $m = - \frac{1}{3}$ $m=-1/3$

As a bonus, we can also see that the y-intercept of the equation is $b = - 3$ $b= -3$

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How do you find the slope given y+3=-1/3x?

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