How do you simplify ${(- 11 x^{3} y)}^{- 2}$ $(-11x^3 y) ^ -2$ ?

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Answer 1 · 2016-03-22T18:04:35

power to power rule on the -2 exponent results in:
${(- 11)}^{- 2} x^{- 6} y^{- 2}$ $(-11)^-2 x^-6 y^-2$

or
$121 x^{- 6} y^{- 2}$ $121x^-6 y^-2$

negative exponents mean reciprocals so this can be further simplified to:

$\frac{121}{x^{6} y^{2}}$ $121/(x^6 y^2)$

How do you simplify (−11x3y)−2(-11x^3 y) ^ -2?