How do you solve #x^2 - 2y = 1# and #x^2 + 5y = 29# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Ch Mar 22, 2016 #x=3# #y=4# Explanation: #x^2-2y=1# → #x^2=1+2y# #x^2+5y=29# Then we substitute the #x^2# in the second equation with #1+2y#. #1+2y+5y=29# #7y=28# #y=4# If #y# is 4 then #x^2=1+2xx4# #x^2=9# #x=sqrt9=3# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1235 views around the world You can reuse this answer Creative Commons License