Question #bb651

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Answer 1 · 2016-03-23T12:46:11

$((9/16)^-3)/2=2^11/3^6$

$a^-n=1/(a^n)$

therefore:

$((9/16)^-3)/2=1/(9/16)^3times1/2=1/(9^3/16^3)times1/2=16^3/9^3times1/2=$

$=(2^4)^3/(3^2)^3times1/2=$

Using the properties

$(a^n)^m=a^(ntimesm)$

$a^n/a^m=a^(n-m)$

$=2^12/3^6times1/2=2^(12-1)/3^6=2^11/3^6$