Two charges of -4 C 4C and -2 C2C are positioned on a line at points -1 1 and 4 4, respectively. What is the net force on a charge of -4 C4C at 1 1?

1 Answer
Mar 28, 2016

F_"net"=28.10^9" N"Fnet=28.109 N

Explanation:

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"The force between two charges is given by formula:"The force between two charges is given by formula:

F=k*(q_1*q_2)/r^2F=kq1q2r2

r:"distance between two charges"r:distance between two charges
q_1:"the first charge"q1:the first charge
q_2:"the second charge"q2:the second charge
F_"AB":" represents the force between charges A and B"FAB: represents the force between charges A and B
F_"CB":"represents the force between charges C and B"FCB:represents the force between charges C and B
F_"AB" and F_"CB" " are opposite forces"FABandFCB are opposite forces
F_"AB"=k*((-4)*(-4))/2^2" "F_"AB"=(16*k)/4=4*kFAB=k(4)(4)22 FAB=16k4=4k

F_"CB"=k*((-2)*(-4))/3^2=" "F_"AB"=(8k)/9FCB=k(2)(4)32= FAB=8k9

F_"net"=F_"AB"-F_"CB"Fnet=FABFCB

F_"net"=4*k-(8*k)/9Fnet=4k8k9

F_"net"=(36*k-8*k)/9Fnet=36k8k9

F_"net"=(28*k)/9" "k=9*10^9 Fnet=28k9 k=9109

F_"net"=(28*cancel(9)*10^9)/cancel(9)

F_"net"=28.10^9" N"