What is the moment of inertia of a rod with a mass of $4 k g$ $4 kg$ and length of $15 m$ $15 m$ that is spinning around its center?

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What is the moment of inertia of a rod with a mass of $4 k g$ $4 kg$ and length of $15 m$ $15 m$ that is spinning around its center?

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Answer 1 · 2016-03-29T01:40:30

$I = \frac{1}{12} \cdot 4 k g \cdot {(15 m)}^{2} = \frac{225}{3} k g \cdot m^{2}$ $I=1/12*4kg*(15m)^2 = 225/3 kg*m^2$

Explanation:

Moment of Inertia, $I = \frac{1}{12} m l^{2}$ $I =1/12 ml^2$
$m = 4 k g; l = 15 m$ $m=4kg; l=15m$
$I = \frac{1}{12} \cdot 4 k g \cdot {(15 m)}^{2} = \frac{225}{3} k g \cdot m^{2}$ $I=1/12*4kg*(15m)^2 = 225/3 kg*m^2$

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What is the moment of inertia of a rod with a mass of $4 k g$ $4 kg$ and length of $15 m$ $15 m$ that is spinning around its center?

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Explanation:

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Science

Math

Humanities

... and beyond

What is the moment of inertia of a rod with a mass of 4kg4 kg and length of 15m15 m that is spinning around its center?

1 Answer

Explanation:

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Impact of this question

What is the moment of inertia of a rod with a mass of $4 k g$ $4 kg$ and length of $15 m$ $15 m$ that is spinning around its center?