What is the moment of inertia of a pendulum with a mass of $8 k g$ $8 kg$ that is $2 m$ $2 m$ from the pivot?

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What is the moment of inertia of a pendulum with a mass of $8 k g$ $8 kg$ that is $2 m$ $2 m$ from the pivot?

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Answer 1 · 2016-03-29T01:52:00

$I = m \cdot r^{2} = 8 \cdot 2^{2} = 2^{5} = 32$ $I= m*r^2 = 8*2^2= 2^5=32$

Explanation:

A pendulum you can treat as point mass of 8 kg, with this in mind you can simply use the straight forward formula $I = m r^{2}$ $I = mr^2$
In general the mass moment of inertia $I_{m} = \int r^{2} d m$ $I_m = int r^2dm$
$I = m \cdot r^{2} = 8 \cdot 2^{2} = 2^{5} = 32$ $I= m*r^2 = 8*2^2= 2^5=32$

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What is the moment of inertia of a pendulum with a mass of $8 k g$ $8 kg$ that is $2 m$ $2 m$ from the pivot?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

What is the moment of inertia of a pendulum with a mass of 8kg8 kg that is 2m2 m from the pivot?

1 Answer

Explanation:

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Impact of this question

What is the moment of inertia of a pendulum with a mass of $8 k g$ $8 kg$ that is $2 m$ $2 m$ from the pivot?